TAG:大智慧

 网友求助:

TJ1:=MA(C,18)<MA(C,50);
TJ2:=V>(REF(V,1)*1.03);
TJ3:=C>(REF(C,1)*1.01);
条件汇总:=TJ1 AND TJ2 AND TJ3;
ma18:=MA(C,18);
mv18:=MA(V,18);
TJ5:ANY(ma18>REF(ma18,1),3) AND ANY(mv18>REF(mv18,1),3) AND EXIST(条件汇总,10);
 

 

解答如下:

TJ1:=MA(C,18)<MA(C,50);
TJ2:=V>(REF(V,1)*1.03);
TJ3:=C>(REF(C,1)*1.01);
条件汇总:=TJ1 AND TJ2 AND TJ3;
MA18:=MA(C,18);
MV18:=MA(V,18);
TJ5:ANY(MA18>REF(MA18,1),3) AND ANY(MV18>REF(MV18,1),3) AND any(条件汇总,10);